一道题

一只音爆

#include<bits/stdc++.h>
using namespace std;
int main(){
	int n , sum=0 ;
	cin >> n ;
	int tybe[n] , money[n] , time[n] ;
	for ( int def = 0 ; def < n ; def ++ ) {
		cin >> tybe[def] >> money[def] >> time[def] ;
 	}
 	
 	for ( int i = 1 ; i < n ; i ++) {
 	    if(tybe[i] && tybe [i-1]==0 && time[i]-time[i-1]<=45){
 			sum += money[i-1];
			continue;
		}else{
			
			sum += money[i];
		}
		
	}
	cout << sum ; 
	return 0 ;
}